Sum of unique/distinct values of a filtered column

Excel_s_o · 27. Januar 2023

Hi CommunityI would like to have a cell of the sum of the budget which updates automatically when you set the filter. Here, every market's budget will count only once. In the example below the sum would be 12+8+5 = 25.If I would filter after A and B, the cell should show a value of 12+8 = 20.Does anyone have an idea who I could solve it?Many thanks in advance.MarketBudgetAnnaA12PeterB8JuliaC5MarcusB8MariaA12

xps350

You are right about numbers not needing quotations marks.

In this case the marks are not delimting numbers, but parts of the sql-string:

- "INSERT INTO tblDetail ([Pid], [Bid]) VALUES ("

- ", "

- ")"

The string is build in this way because it consists of fixed parts (see above) and variable parts (the
values of lngProductID and lngBID).

Irish Beast

und eine noch eventuel duemmere Frage, das klappt nur so einfach wenn der Referenzbereich von A: ist.

Wenn er aber von F: ist dann muesste ich so arbeiten

=VLOOKUP(C2,F:G,SUM(COLUMN(G:G)-COLUMN(F:F))+1,FALSE)

richtig? Oder gibt es da einen noch einfacheren Weg?

Vijay_Verma

Hi Fatima

Greetings! I am Vijay, an Independent Advisor. You can use VLOOKUP very easily.

Let's say that your second list has list of items in column E (please change E appropriately). Data starts in row 2.

And first list in column A and B of same sheet. Use following formula and drag down

=VLOOKUP(E2,A:B,2,0)

More robustly

=IFERROR(VLOOKUP(E2,A:B,2,0),"")

Now there may be a scenario that first list is in Sheet1 and second list is in another sheet starting in column A.

The use following formulas

=VLOOKUP(A2,'Sheet1'!A:B,2,0)

=IFERROR(VLOOKUP(A2,'Sheet1'!A:B,2,0),"")

Wil1969

Hi Minhokiller,
 thanks for your effort. The translation didn't understand that I wanna have a complete row colored in reference to to values of certain cells.
 Best reguards
 Wil
 P.s.: Ich weiß, Deutsches Forum.

Lisa Wilke-Thissen

Hi,

not a bug, but a feature ;-) of all versions of Word.

Viele Grüße

Lisa

Hi,

willkommen im Windows Forum!

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